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Answer:
The work done on the box is 21.952 Joules
Explanation:
The given parameters are;
The mass of the box of magazines, m = 1.4 kg
The upward force with which the student lifts the magazine = 52.7 N
The distance (height) of the lift, h = 1.6 meters
The work done on the box = The potential energy gained by the box of magazine, P. E.
Potential energy gained by elevation, P. E. = Mass, m × The acceleration due to gravity, g × Height, h
Where;
The acceleration due to gravity, g = 9.8 m/s²
∴ P. E. = m × g × h = 1.4 kg × 9.8 m/s^2 × 1.6 m = 21.952 Joules
The work done on the box = The potential energy gained by the box of magazine, P. E. = 21.952 Joules
The total work done on the box is 21.952 Joules
The workdone on the box is equal to the potential energy possessed by the body. Mathematically;
[tex]W=P.E=mgh[/tex]
Given the following parameters
m = 1.4kg
g = 9.8m/s²
h = 1.6m
Substitute the given parameters into the formula:
[tex]W = 1.4 \times 9.8 \timees 1.6\\W=21.952Joules[/tex]
Hence the total work done on the box is 21.952 Joules
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