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Sagot :
Answer:
The weight of the object when it is lifted to 3 times the height is 33.[tex]\overline 3[/tex] N
Explanation:
The given parameters are;
The weight of the object on Earth, W = 300 N
The initial position of the object = On the surface of the Earth
Therefore;
The distance with which the weight is measured = The radius of the Earth, R
By Newton's Law of Gravitation, we have;
[tex]W = G \times \dfrac{M \times m}{R^2}[/tex]
Where;
W = 200 N
G = The universal gravitational constant
M = The mass of the Earth
m = The mass of the object
When the height of the object = 3 × R, the weight of the object, W₂, is given as follows;
[tex]W_2 = G \times \dfrac{M \times m}{(3 \times R)^2} = \dfrac{1}{9} \times G \times \dfrac{M \times m}{ R^2} = \dfrac{1}{9} \times W = \dfrac{1}{9} \times 300 N = 33.\overline 3 \ N[/tex]
Therefore, the weight of the object at 3 times the height, W₂ = 33.[tex]\overline 3[/tex] N
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