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Can anyone please teach me how to work out x2-8x+19?

Sagot :

Konrad509idn
[tex]x^2-8x+19=\\ x^2-8x+16+3=\\ (x-4)^2+3\\\\ (x-4)^2+3=0\\ (x-4)^2=-3\\ x\in \emptyset[/tex]
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