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Solve for X and solve for Y?

Solve For X And Solve For Y class=

Sagot :

Answer:

[tex] x=3\sqrt 5\\[/tex]

[tex]y = \sqrt {126}[/tex]

Step-by-step explanation:

By geometric mean property:

[tex]x = \sqrt{9 \times 5} = \sqrt{45} = 3 \sqrt{5} \\ \\ by \: pythagoras \: theorem \\ \\ {y}^{2} = {9}^{2} + {x}^{2} \\ \\ {y}^{2} = {9}^{2} + {(3 \sqrt{5}) }^{2} \\ \\ {y}^{2} = 81 + 45 \\ \\ {y}^{2} = 126 \\ \\ y = \sqrt{126} [/tex]