Answer:
[tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}[/tex]
Hence, ption B is true.
Step-by-step explanation:
Given the expression
[tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex]
solving the expression
[tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex]
as
[tex]\sqrt{x^2y^3}=xy\sqrt{y}[/tex]
[tex]2\sqrt{x^3y^4}=2xy^2\sqrt{x}[/tex]
so the expression becomes
[tex]\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}[/tex]
Group like terms
[tex]=2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}[/tex]
Add similar elements
[tex]=2xy^2\sqrt{x}+2xy\sqrt{y}[/tex]
Therefore, we conclude that:
[tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}[/tex]
Hence, option B is true.
