Answer:
[tex]3x^8\sqrt{11x}[/tex]
Step-by-step explanation:
[tex]\sqrt{99x^{17}}[/tex]
First we have to break the 99 up into 9 and 11. Since 9 is a perfect square, it'll come out perfect. Then for the x to the power of 17 we will make the exponent into an even number by taking one x away.
[tex]\sqrt{99x^{17}}\\\sqrt{9x^{16}}\sqrt{11x}[/tex]
So after we have this simplify the perfect square and don't touch the non-perfect ones.
[tex]\sqrt{99x^{17}}\\\sqrt{9x^{16}}\sqrt{11x}\\3x^8\sqrt{11x}[/tex]
So that's it!
