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What is the smallest value of an angle, , by which a regular pentagon should be rotated about its center x so that it carries onto itself?

Sagot :

Answer:

[tex]x = 72^{\circ}[/tex]

Explanation:

Given

Shape: Regular Pentagon

Required

Determine the minimum value of x

A pentagon has 5 sides and 1 complete rotation of a pentagon about its centre is 360 degrees

i.e.

[tex]1\ Rotation = 360^{\circ}[/tex]

[tex]Sides= 5[/tex]

The angle of rotation (x) is then calculated as:

[tex]x = \frac{1\ Rotation}{Sides}[/tex]

Substitute values for 1 rotation and sides

[tex]x = \frac{360^{\circ}}{5}[/tex]

[tex]x = 72^{\circ}[/tex]

The above is the minimum value of rotation.

As a bonus

Other possible angle of rotation must be in multiples of 72

i.e.

[tex]x = 72, 144, 216, 288,360....[/tex]

This means that when the pentagon is rotated in any of the above angles of rotation, it will be carried onto itself.