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5. Calculate the number of moles of potassium nitrate, KNO3, in a sample with a mass of 85.2 grams.

Sagot :

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Answer:

0.843 mol KNO₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

Step 1: Define

85.2 g KNO₃

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

Step 3: Convert

[tex]\displaystyle 85.2 \ g \ KNO_3(\frac{1 \ mol \ KNO_3}{101.11 \ g \ KNO_3} )[/tex] = 0.842647 mol KNO₃

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.842647 mol KNO₃ ≈ 0.843 mol KNO₃

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