Answer:
from the graph, there is point (1,3) and (-2,-3).
[tex]slope, \: m = \frac{(y _{2} - y _{1})}{(x _{2} - x _{1}) } \\ m = \frac{( - 3 - 3)}{( - 2 - 1)} \\ m = \frac{ - 6}{ - 3} \\ m = 2 \\ from \: general \: equation \: of \: a \: line \\ y = mx + c \\ consider \: point \: (1,3) \\ 3 = (2)(1) + c \\ 3 = 2 + c \\ c = 3 - 2 \\ c = 1 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y = 2x + 1[/tex]
Answer: D => y=2x+1
