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The base of a triangle is....

The Base Of A Triangle Is class=

Sagot :

Answer:

[tex]a=49[/tex]

Step-by-step explanation:

You would solve this the same way you would with any other triangle problem. You will plug in for the base and the height in this formula [tex]a=\frac{1}{2}bh[/tex].

[tex]a=\frac{1}{2}bh\\a=\frac{1}{2}(\sqrt{343})(\sqrt{28})[/tex]

Now we will multiply the two radicands.

[tex]a=\frac{1}{2}\sqrt{9604}[/tex]

For this we will split the 9604 into 49 and 196.

[tex]a=\frac{1}{2}\sqrt{49}\sqrt{196}[/tex]

Now we just take the square roots of those two and since they're perfect squares they'll be whole numbers.

[tex]a=\frac{1}{2}(7)(14)[/tex]

Next we just multiply everything together.

[tex]a=49[/tex]

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