Answer:
[tex]2y\sqrt{2x}[/tex]
Step-by-step explanation:
For this we have to divide like normally but for the exponents we will subtract them since this is a division problem. We would've added them if we were multiplying.
[tex]\frac{\sqrt{32x^5y^8}}{\sqrt{4x^4y^6}}=\sqrt{8xy^2}[/tex]
Now we will split the 8 into 4 and 2. Also we can take the square root of y² while we're at it.
[tex]y\sqrt{4}\sqrt{2x}[/tex]
Now we take the square root of 4.
[tex]2y\sqrt{2x}[/tex]
