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Answer:
The molar concentration of HF is 0.34 M
Explanation:
Given data:
Molarity of NaOH =M₁ = 0.200 M
Volume of HF =V₂= 18.25 mL
Volume of NaOH added = V₁ = 31.20 mL
Molarity of HF solution = M₂ = ?
Solution:
M₁V₁ = M₂V₂
by putting values,
0.200 M × 31.20 mL = M₂ × 18.25 mL
M₂ = 0.200 M × 31.20 mL / 18.25 mL
M₂ = 6.24 M.mL / 18.25 mL
M₂ = 0.34 M
Thus, the molar concentration of HF is 0.34 M.