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In ΔIJK, k = 3.6 inches, i = 1.3 inches and ∠J=13°. Find the length of j, to the nearest 10th of an inch.

Sagot :

Clarch19idn

Answer:

5.6 inches

Step-by-step explanation:

let c = length of 'j'

I used the Law of Cosines:  [tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] -2ab· cosC

= (1.3)^2 + (3.6)^2 - 2(1.3)(3.6) x 0.97

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