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Pascha is factoring the polynomial, which has four terms.


3x3 – 15x2 + 8x – 40


3x2(x – 5) + 8(x – 5)


Which is the completely factored form of her polynomial?


(3x2 – 5) (x + 8)

(3x2 – 8) (x + 5)

(3x2 + 8) (x – 5)

(3x2 + 5) (x – 8)


Sagot :

Answer:

[tex](3x^2 + 8)(x - 5)[/tex]

Step-by-step explanation:

Given

[tex]3x^3 - 15x^2 + 8x - 40 = 3x^2(x - 5) + 8(x - 5)[/tex]

Required

Complete the factorization

[tex]3x^3 - 15x^2 + 8x - 40 = 3x^2(x - 5) + 8(x - 5)[/tex]

When an equation is factorized as:

[tex]a(b + c) + d(b + c)[/tex]

The complete expression is:

[tex](a + d)(b + c)[/tex]

Apply this logic in [tex]3x^3 - 15x^2 + 8x - 40 = 3x^2(x - 5) + 8(x - 5)[/tex]

By comparison:

[tex]a = 3x^2; b = x; c = -5; d = 8[/tex]

So, we have:

[tex]3x^3 - 15x^2 + 8x - 40 = (3x^2 + 8)(x - 5)[/tex]

Hence,

[tex](3x^2 + 8)(x - 5)[/tex] is the complete factor

Answer:

c

Step-by-step explanation: