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Answer: max Ag2S 159 g
Explanation:
at wts Ag 107.87, I 126.9, Na 22.99, S 32.065
AgI 234.76, Na2S 87.12, Ag2S 172.0, NaI 149.6
2(mol)AgI + 1(mol)Na2S —> 1(mol)Ag2S + 2(mol)NaI
200g AgI = 200/107.87 mol = 1.85 mol
200g Na2S = 200/87.12 mol = 2.3 mol, so AgI is limiting.
2 mol AgI —> 1 mol Ag2S, so
1.85 mol AgI —> 1.85/2 mol Ag2S
1 mol Ag2S = 172 g
max Ag2S = 172*1.85/2 g = 159g