Answer:
[tex]\sin(2\theta) =2 \sin \theta \cos \theta[/tex] proved
Step-by-step explanation:
Given
[tex]\sin2 \theta=2 \sin\theta cos\theta[/tex]
Required
Prove
Proving from left to right.
[tex]\sin(2\theta) = \sin(\theta+\theta)[/tex]
In trigonometry
[tex]\sin(A+B) = \sin A \cos B+\sin B \cos A[/tex]
When this formula is applied to:[tex]\sin(2\theta) = \sin(\theta+\theta)[/tex]
We have:
[tex]\sin(2\theta) = \sin \theta \cos \theta+\sin \theta \cos \theta[/tex]
[tex]\sin(2\theta) =2 \sin \theta \cos \theta[/tex]
Proved
