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What is the equation of the line shown?

What Is The Equation Of The Line Shown class=

Sagot :

Step-by-step explanation:

Hey there!

According to the figure, we find two points on graph. I.e (1,3) and (-2,-1) points respectively.

Now, Use double point formula for finding the eqaution.

[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]

Keep all values.

[tex](y - 3) = \frac{( - 1 - 3)}{ (- 2 - 1)}(x - 1) [/tex]

~ Simplify it.

[tex](y - 3) = \frac{4}{3} (x - 1)[/tex]

[tex](y - 3) = \frac{4}{3} x - \frac{4}{3} [/tex]

[tex]y = \frac{4}{3} x - \frac{4}{3} + 3 [/tex]

[tex]y = \frac{4}{3} x + \frac{5}{3} [/tex]

Therefore, the equation of the line is y= 4/3x + 5/3.

Hope it helps...

Answer:

y = [tex]\frac{4}{3}[/tex] x + [tex]\frac{5}{3}[/tex]

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, - 1) and (x₂, y₂ ) = (1, 3) ← 2 point on the line

m = [tex]\frac{3+1}{1+2}[/tex] = [tex]\frac{4}{3}[/tex] , then

y = [tex]\frac{4}{3}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, 3 ), then

3 = [tex]\frac{4}{3}[/tex] + c ⇒ c = 3 - [tex]\frac{4}{3}[/tex] = [tex]\frac{5}{3}[/tex]

y = [tex]\frac{4}{3}[/tex] x + [tex]\frac{5}{3}[/tex] ← equation of line