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Sagot :
Answer:
[tex]\frac{dr}{da} = \frac{3a^2 + 2a + 7}{2a^{\frac{3}{2} }}[/tex]
General Formulas and Concepts:
Pre-Algebra
- Distributive Property
Algebra I
- Expand by FOIL (First Outside Inside Last)
- Terms/Coefficients/Degrees
Algebra II
- Exponential Rule: [tex]x^{-m}= \frac{1}{x^m}[/tex]
- Exponential Rule: [tex]\sqrt{x} = x^{\frac{1}{2} }[/tex]
Calculus
Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Quotient Rule: [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]
Step-by-step explanation:
Step 1: Define
[tex]r = \frac{a^2+2a-7}{\sqrt{a}}[/tex]
Step 2: Rewrite
[tex]r = \frac{a^2+2a-7}{a^{\frac{1}{2} }}[/tex]
Step 3: Differentiate
- Quotient Rule [Basic Power: [tex]\frac{dr}{da} = \frac{a^{\frac{1}{2} }(2a^{2-1} + 2a^{1-1}) - \frac{1}{2}a^{\frac{1}{2} - 1 }(a^2 + 2a + 7)}{(a^{\frac{1}{2} })^2}[/tex]
- Simplify: [tex]\frac{dr}{da} = \frac{a^{\frac{1}{2} }(2a + 2) - \frac{1}{2}a^{-\frac{1}{2}}(a^2 + 2a + 7)}{a}[/tex]
- Simplify: [tex]\frac{dr}{da} = \frac{2}{2} \cdot \frac{a^{\frac{1}{2} }(2a + 2) - \frac{1}{2}a^{-\frac{1}{2}}(a^2 + 2a + 7)}{a}[/tex]
- Multiply: [tex]\frac{dr}{da} = \frac{2a^{\frac{1}{2} }(2a + 2) - a^{-\frac{1}{2}}(a^2 + 2a + 7)}{2a}[/tex]
- Factor: [tex]\frac{dr}{da} = \frac{a^{-\frac{1}{2}}[2a(2a + 2) - (a^2 + 2a + 7)]}{2a}[/tex]
- [Brackets] Distribute: [tex]\frac{dr}{da} = \frac{a^{-\frac{1}{2}}[4a^2 + 4a - a^2 - 2a - 7]}{2a}[/tex]
- [Brackets] Combine Like Terms: [tex]\frac{dr}{da} = \frac{a^{-\frac{1}{2}}[3a^2 + 2a - 7]}{2a}[/tex]
- Simplify: [tex]\frac{dr}{da} = \frac{3a^2 + 2a + 7}{2a^{\frac{3}{2} }}[/tex]
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