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Louise is 56 3 /4 inches tall. Theresa is 1 1 /2 inches shorter than Louise and Jane is 1 1/ 5 inches shorter than Theresa. How tall is Jane?

Sagot :

JeanaShuppidn

Answer: [tex]54\dfrac1{20}\text{ inches}[/tex]

Step-by-step explanation:

Given:  Height of Louise  = [tex]56\dfrac34 \text{ inches }=\dfrac{4\times56+3}{4}=\dfrac{227}{4}\text{ inches}[/tex]

Then , height of Theresa = Height of Louise  [tex]-1\dfrac{1}{2}\text{ inches}[/tex]

[tex]=\dfrac{227}{4}-\dfrac{3}{2}\text{ inches}\\\\=\dfrac{227-6}{4}=\dfrac{221}{4}\text{ inches}[/tex]

Height of jane = height of Theresa - [tex]1\dfrac15[/tex] inches

[tex]=\dfrac{221}{4}-1\dfrac15\text{ inches}\\\\=\dfrac{221}{4}-\dfrac{6}{5}\text{ inches}\\\\=\dfrac{5\times221-6\times4}{20}\text{ inches}\\\\=\dfrac{1105-24}{20}=\dfrac{1081}{20}\text{ inches}\\\\= 54\dfrac1{20}\text{ inches}[/tex]

Hence,  Jane is  [tex]54\dfrac1{20}\text{ inches}[/tex] tall.

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