Question:
Two red and two blue blocks....
Answer:
[tex]P(Not\ Blue) = \frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]Red = 2[/tex]
[tex]Blue = 2[/tex]
Required
Probability of not selecting blue
First, we calculate the probability of selecting blue
[tex]P(Blue) = \frac{Blue}{Total}[/tex]
[tex]P(Blue) = \frac{2}{2+2}[/tex]
[tex]P(Blue) = \frac{2}{4}[/tex]
[tex]P(Blue) = \frac{1}{2}[/tex]
In probability:
Opposite probabilities sum up to 1 i.e.
[tex]P(Blue) + P(Not\ Blue) = 1[/tex]
This gives
[tex]\frac{1}{2} + P(Not\ Blue) = 1[/tex]
[tex]P(Not\ Blue) = 1 - \frac{1}{2}[/tex]
[tex]P(Not\ Blue) = \frac{2-1}{2}[/tex]
[tex]P(Not\ Blue) = \frac{1}{2}[/tex]
