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If square A has a side of length 5 inches, how many times bigger is the area of square B if it has a side of length 25 inches?

Sagot :

Answer:

24 times

Step-by-step explanation:

It is given that :

The length of the side of square A = 5 inches

The length of the side of square B = 25 inches

Therefore, area of square A = 5 x 5

                                               = 25 square inches

Similarly, area of square B = 25 x 25

                                            = 625 square inches

Therefore, number of times the square B is bigger than the square A is given by :

[tex]$=\frac{625-25}{25}$[/tex]

[tex]$=\frac{600}{25}$[/tex]

= 24

Thus the square B is 24 times bigger than square A