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Sagot :
Answer:
(a) Zeroes of the function is -2,4.
(b) The vertex of the parabola is (1,-9).
Step-by-step explanation:
Given,
f(x)=(x+2)(x−4)
(a)To find the zeros of the function put f(x)=0.
(x+2)(x-4)=0
x+2 = 0 or x-4 = 0
x = -2,4
Hence, zeroes of the function is -2,4.
(b)Now,
f(x)=(x+2)(x−4)
[tex]f(x)= x^2 -2x+1 -1-8[/tex]
[tex]f(x)= (x-1)^2-9[/tex] .......(i)
We know that,
If [tex]f(x)=a(x-h)^2 +k[/tex] is the equation of parabola the (h,k) is the vertex of the parabola.
On comparing with equation (i), we get
h = 1
k = -9
Hence, the vertex of the parabola is (1,-9).
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