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Which equation shows how to calculate how many grams (g) of KCI would be
produced from 4 mol KOH? The balanced reaction is:
MgCl2 + 2KOH → Mg(OH)2 + 2KCI
A.4 mol KOH
1
2 mol KCI
1 mol KOH
74.55 g KCI
1 mol KCI
4 mol KOH
X
B.1 mol KCI
2 mol KOH
X
74.55 g KCI
1 mol KCI
4 mol KOH
C.X
2 mol KCI
2 mol KOH
X
74.55 g KCI
1 mol KCI
4 mol KOH
X
X
D.o
1 mol KOH
1 mol KCI
74.55 g KCI
1 mol KCI
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