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If BD bisects AC and AC bisects BD, is ABE ≅ CDE? Explain.

A. Yes; the triangles are congruent by AAS.

B. Yes; the triangles are congruent by ASA.

C. Yes; the triangles are congruent by SAS.

D. No; the triangles are not congruent.


Sagot :

Answer:

C. Yes; the triangles are congruent by SAS.

Step-by-step explanation:

From the question, we understand that:

AC and BD bisects one another

The bisection is better illustrated with a diagram. (See attachment).

From this point, I'll use the attachment as a point of reference.

From the attachment:

[tex]AE = CE[/tex] --- Side

and

[tex]BE = DE[/tex] --- Side

When both lines bisect one another, they form a pair of vertical angles [tex]\angle AEB[/tex] and [tex]\angle CED[/tex]

When we apply the theorem of vertical angles to this, we have that:

[tex]\angle AEB[/tex] [tex]=[/tex] [tex]\angle CED[/tex] --- Angle

At this point, we have established:

Two sides of ABE and CDE are congruent

and

One angle in each of ABE and CDE are also congruent

Hence, the triangles are congruent by SAS.

View image MrRoyal