Get the answers you've been searching for with IDNLearn.com. Discover the information you need quickly and easily with our reliable and thorough Q&A platform.

A motorboat travels 172 km in 3 hours going upstream and 372 in 4 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?

Sagot :

Answer:

The rate of the boat is 75.17 km/h and the rate of the stream is 17.83 km/h

Step-by-step explanation:

System of Equations

Let's call:

B = speed (rate) of the boat in still water

S = speed (rate) of the stream

The boat travels 172 km in 3 hours when going upstream, that is when the speed of the stream subtracts its own speed. The speed is the distance divided by the time, thus:

[tex]\displaystyle B-S=\frac{172}{3}[/tex]

Multiplying by 3:

3B - 3S = 172        [1]

The boat travels 372 km in 4 hours downstream when the speed of the current adds to its own:

[tex]\displaystyle B+S=\frac{372}{4}=93[/tex]

B + S = 93

Solving for B:

B = 93 - S       [2]

Substituting in [1]

3(93 - S) - 3S = 172

Operating:

279 - 3S - 3S = 172

279 - 6S = 172

Subtracting 279:

- 6S = 172 - 279

- 6S = -107

Multiplying by -1 and solving for S:

[tex]S = \frac{107}{6}\approx 17.83\ km/h[/tex]

From [2]:

[tex]B = 93 - \frac{107}{6}[/tex]

[tex]B=\frac{451}{6}\approx 75.17\ km/h[/tex]

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.