StreetFighterLan123idn
Answered

Find trusted answers to your questions with the help of IDNLearn.com's knowledgeable community. Discover comprehensive answers to your questions from our community of knowledgeable experts.

Find the values of b such that the function has the given maximum value [tex]f(x) = -x^2+bx-65[/tex]. I already have it in vertex form as [tex]-(x+\frac{b}{2})^2-65+\frac{b^2}{4}[/tex] but I don't know what to do from here

Sagot :

Mhanifaidn

Answer:

  • b = {20, -20}

Step-by-step explanation:

Given function:

  • f(x) = -x² + bx - 65 with maximum value of 35

To find

  • The value of b

Solution:

Maximum value is obtained at vertex as a < 0

Vertex coordinate of x is:

  • x = -b/2a = -b / -2 = 1/2b

Solving for b:

  • 35 = - (1/2b)² + b(1/2b) - 65
  • - 1/4b² + 1/2b² = 100
  • 1/4b² = 100
  • b² = 400
  • b = √400
  • b = ± 20

See attached

View image Mhanifa
We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.