Answer:
(0, 2 ) and (- [tex]\frac{4}{3}[/tex], [tex]\frac{2}{9}[/tex] )
Step-by-step explanation:
Given the 2 equations
2x² + 4x - y = - 2 → (1)
x² + y = 2 → (2)
subtract x² from both sides in (2)
y = 2 - x² → (3)
Substitute y = 2 - x² into (1)
2x² + 4x - (2 - x²) = - 2
2x² + 4x - 2 + x² = - 2
3x² + 4x - 2 = - 2 ( add 2 to both sides )
3x² + 4x = 0 ← in standard form
x(3x + 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x = 0
3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = - [tex]\frac{4}{3}[/tex]
Substitute these values into (3) for corresponding values of y
x = 0 : y = 2 - 0² = 2 - 0 = 2 ⇒ (0, 2)
x = - [tex]\frac{4}{3}[/tex] : y = 2 - (- [tex]\frac{4}{3}[/tex] )² = 2 - [tex]\frac{16}{9}[/tex] = [tex]\frac{2}{9}[/tex] ⇒ ( - [tex]\frac{4}{3}[/tex], [tex]\frac{2}{9}[/tex] )
