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Two inductors are connected in series to a 120 volt, 60 Hz line. The values are .75 H and 1.47 H. The total inductive reactance is

Sagot :

Samuelonum1idn

Answer:

837.02 ohms

Explanation:

Step one:

Given data

Frequency= 60Hz

L1= 0.75H

L2= 1.47H

When inductors are connected in series, the total inductance is the sum of the individual inductance

Step two:

Inductor 1

[tex]Xl1= 2\pi fL\\\\Xl1= 2*3.142*60*0.75\\\\Xl1= 282.78 ohms[/tex]

Inductor 2

[tex]Xl2= 2\pi fL\\\\Xl2= 2*3.142*60*1.47\\\\Xl2= 554.24 ohms[/tex]

The total inductance is

=282.78+554.24

=837.02 ohms

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