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A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross section of the wire

Sagot :

Answer: 162500000

Explanation:

given data:

wire diameter = 1.8mm

wire length = 15cm

current = 260mA.

electron charge e = [tex]1.6*10^{-19} C[/tex]

Solution:

[tex]I = \frac{q}{t}[/tex]

where:

[tex]I = current\\\\q = charge\\\\t = time \\\\q=It\\\\q= 260mt[/tex]

[tex]q=ne\\\\n = \frac{q}{e} \\\\n= \frac{260*10^{-3} t}{1.6*10^{-19} } \\\\n= 162500000t\\\\\frac{n}{t} = 162500000[/tex]

number of electrons per seconds would be 162500000