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Sagot :
Answer: 162500000
Explanation:
given data:
wire diameter = 1.8mm
wire length = 15cm
current = 260mA.
electron charge e = [tex]1.6*10^{-19} C[/tex]
Solution:
[tex]I = \frac{q}{t}[/tex]
where:
[tex]I = current\\\\q = charge\\\\t = time \\\\q=It\\\\q= 260mt[/tex]
[tex]q=ne\\\\n = \frac{q}{e} \\\\n= \frac{260*10^{-3} t}{1.6*10^{-19} } \\\\n= 162500000t\\\\\frac{n}{t} = 162500000[/tex]
number of electrons per seconds would be 162500000
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