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Answer:
[tex]\huge\boxed{t=3}[/tex]
Step-by-step explanation:
[tex]-5(t+3)=-30[/tex]
[tex]-5(t+3)=-30[/tex] divide both sides by (-5)
[tex]\dfrac{-5\!\!\!\!\diagup(t+3)}{-5\!\!\!\!\diagup}=\dfrac{-30}{-5}[/tex]
[tex]t+3=6[/tex] subtract 3 from both sides
[tex]t+3-3=6-3\\t=3[/tex]
[tex]-5(t+3)=-30[/tex] use the distributive property a(b + c) = ab + ac
[tex](-5)(t)+(-5)(3)=-30[/tex]
[tex]-5t-15=-30[/tex] add 15 to both sides
[tex]-5t-15+15=-30+15[/tex]
[tex]-5t=-15[/tex] divide both sides by (-5)
[tex]\dfrac{-5t}{-5}=\dfrac{-15}{-5}\\\\t=3[/tex]