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Solve. Round to the nearest tenth.
6
2-12
19
2x-2
HELP ASAP!!

Solve Round To The Nearest Tenth 6 212 19 2x2 HELP ASAP class=

Sagot :

Spaceidn

Answer:

[tex]\displaystyle x = \frac{216}{7}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \frac{6}{19} = \frac{x - 12}{2x - 2}[/tex]

Step 2: Solve for x

  1. Cross-multiply:                     [tex]\displaystyle 6(2x - 2) = 19(x - 12)[/tex]
  2. Distribute:                             [tex]\displaystyle 12x - 12 = 19x - 228[/tex]
  3. Isolate x terms:                     [tex]\displaystyle -12 = 7x - 228[/tex]
  4. Isolate x term:                      [tex]\displaystyle 216 = 7x[/tex]
  5. Isolate x:                               [tex]\displaystyle \frac{216}{7} = x[/tex]
  6. Rewrite:                                [tex]\displaystyle x = \frac{216}{7}[/tex]
Manissaha129idn

Answer:

[tex] \frac{6}{19} = \frac{x - 12}{2x - 2} \\ 6(2x - 2) = 19(x - 12) \\ 12x - 12 = 19x - 228 \\ 7x = 216 \\ \boxed{x = 30.857}[/tex]

30.857 is the right answer.

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