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A beaker is filled to the 500 ml mark with alcohol. What increase in volume (in ml) the beaker contain when the temperature changes from 5°C to 30°C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) C°, Palcohol = 1.12 x 104/ °C

Sagot :

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Answer:

1.4 mL

Explanation:

Given that:

volume of alcohol [tex]V_0[/tex] = 500

Temperature change ΔT = (30° - 5°)C

=25° C

[tex]\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C[/tex]

The increase in volume ΔV =  [tex]\alpha \times V_o \times \Delta T[/tex]

[tex]= 500 \times 1.12 \times 10^{-4} / ^0 C\times 25^0 C[/tex]

= 1.4 mL

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