Tikihut21savageidn
Answered

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SELECT ALL The Points that are on the Graph of the line 3x + 2y = 28 (:

SELECT ALL The Points That Are On The Graph Of The Line 3x 2y 28 class=

Sagot :

Answer:

(0,14) and (2,11)

Step-by-step explanation:

points are on the graph of the line:-

[tex]\tt{3x+2y=28 }[/tex] ⠀

we get,

[tex]\rightsquigarrow[/tex] [tex]\tt{ 2y=28-3x }[/tex] ⠀

[tex]\rightsquigarrow[/tex] [tex]\tt{y=\dfrac{28-3x}{2} }[/tex] ⠀

In,(0,14)

If we put the value ,x=0

y=[tex]\tt{\dfrac{ 28-3×0}{2}=\dfrac{28}{2}=14 }[/tex]

So,we get one point,(0,14)✔

In,(2,11)

If we put ,x=2

y=[tex]\tt{\dfrac{28-3×2}{2}=\dfrac{28-6}{2}=\dfrac{22}{2}=11 }[/tex]

so,we get another point (2,11)✔

in other given ponts{(1,12),(4,9),(8,4)},It is impossible. ⠀ ⠀

Lucky75idn

we have to find the line which are in the line!!

points are on the graph of the line:-

3x+2y=28 ⠀

we get,

2y=28−3x ⠀

[tex]{y=\dfrac{28-3x}{2} }[/tex]

In,(0,14)

If we put the value ,x=0

[tex]y={\dfrac{ 28-3×0}{2}=\dfrac{28}{2}=14 }[/tex]

so one point is (0,14)

In,(2,11)

If we put ,x=2

[tex]y={\dfrac{28-3×2}{2}=\dfrac{28-6}{2}=\dfrac{22}{2}=11 }[/tex]

so,we get another point (2,11)

in other given ponts{(1,12),(4,9),(8,4)},It is impossible. ⠀ ⠀

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