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A family is skating at an ice rink. The 58.2 kg mother is holding the
hand of her 35.5 kg daughter. The father grabs his wife's free hand and pulls horizontally with a constant force of 100. N. Assume that the skates glide without friction on the ice and that the family's hands andarms approximate ideal strings. How much net force does the daughter experience?

Sagot :

Answer:

When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.

Explanation:

use this formula :

[tex]a_{y}[/tex] = [tex]\frac{Fdadshandy}{msys}[/tex]

then you fill it in :

[tex]a_{y}[/tex] = [tex]\frac{100N}{35.5kg+58.2kg}[/tex]

[tex]a_{y}[/tex] = [tex]\frac{100N}{93.7kg}[/tex]

[tex]a_{y}[/tex] = [tex]1.0672[/tex] [tex]m/s^{2}[/tex]

then you multiply that with the daughters weight :

[tex]T_{2} x= m_{2} a_{y}[/tex]

[tex]T_{2} x = 35.5kg (1.0672 m/s^{2})[/tex]

[tex]T_{2} x = 37.89N[/tex]

and that's the answer :) : 37.89N

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