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What is the equation of the line that passes through the point (2, -2) and has a
slope of -1/2?

Sagot :

Answer:

Step-by-step explanation:

use the point-slope formula [y-y1 =m(x-x1) ] with the given info

for the point P=(x1,y1) =(2,-2) and the slople m = -1/2

plug those into the formula

y-(-2)= -1/2(x-2)

y+2= -1/2x + 1

y= -1/2x+1 - 2

y = -1/2x - 1

:)  got it?  

these are hard untill you get the idea of the two formulas  

point-slope:         y-y1 = m(x-x1)  and

slope-intercept:   y= mx+b

memorizing those will help a lot

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