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Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°​

Select The Correct Answer For What Value Of X Is Sin X Cos 19º Where 0lt X Lt 90 OA 38 O B 71 OC 26 O D 19 class=

Sagot :

Absor201idn

Answer:

x = 71°

Option B is correct answer.

Step-by-step explanation:

We need to find for what value of x is [tex]sin\: x = cos 19^{\circ}[/tex], where 0°< x < 90°?

Solving:

[tex]sin\: x = cos\: 19^{\circ}\\Finding \:cos\: 19^{\circ}=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^{-1}(0.94551)\\x=71^{\circ}[/tex]

So, we get x = 71°

Option B is correct answer.

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