Laurenthetutoridn
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36x^3 +27x^2=0 pls help me solve :/​

Sagot :

Answer:          36x^3 +27x^2 = 9x^2\left(4x+3\right)

Step-by-step explanation: apply exponent rule rewrite factor out common term plz enjoy

Tekashiiidn

Answer:

[tex]x = 0\; ,-\frac{3}{4}[/tex]

Step-by-step explanation:

[tex]36x^3 + 27x^2 = 0[/tex]

  • Take 9x² common from the expression on L.H.S.

[tex]=> 9x^2(4x + 3) = 0[/tex]

Here, x will have 2 values :-

1) [tex]9x^2(4x + 3) = 0[/tex]

  • Divide both the sides by (4x + 3)

[tex]=> \frac{9x^2(4x + 3)}{(4x+3)} = \frac{0}{4x+3}[/tex]

[tex]=> 9x^2 = 0[/tex]

  • Divide both the sides by 9x

[tex]=> \frac{9x^2}{9x} = \frac{0}{9x}[/tex]

[tex]=> x = 0[/tex]

2) [tex]9x^2(4x + 3) = 0[/tex]

  • Divide both the sides by 9x²

[tex]=> \frac{9x^2(4x + 3)}{9x^2} = \frac{0}{9x^2}[/tex]

[tex]=> 4x+3 = 0[/tex]

  • Substract both the sides from 3

[tex]=> 4x+3 -3 = 0 - 3[/tex]

[tex]=> 4x=-3[/tex]

  • Divide both the sides by 4

[tex]=> \frac{4x}{4} = \frac{-3}{4}[/tex]

[tex]=> x = -\frac{3}{4}[/tex]

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