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Many families in California are using backyard structures for home offices, art studios, and hobby areas as well as for additional storage. Suppose that the mean price for a customized wooden, shingled backyard structure is $3,200. Assume that the standard deviation is $1,200. (a) What is the z-score for a backyard structure costing $2,300

Sagot :

Ogorwyneidn

Answer:

-0.75

Step-by-step explanation:

To get the z score we have to use this formula

Z = X-mean/standard deviation

X = 2300

Mean = 3200

The standard deviation = 1200

When we plug these values into the z formula above, we have:

2300-3200/1200

= -900/1200

= -0.75

the z-score for a backyard structure costing $2,300 is therefore -0.75

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