Explanation:
Given parameters:
Number of cycles = 10cycles
Time taken = 50s
Unknown:
Period of its rotation = ?
Frequency of its rotation = ?
Solution:
The period of rotation is the time taken time taken for a body to complete a number of rotation;
Period = [tex]\frac{t}{n}[/tex]
t is the time
n is the number of cycles
Period = [tex]\frac{50}{10}[/tex] = 5s
The period is 5s
Now, frequency is the inverse of period;
F = [tex]\frac{1}{period}[/tex] = [tex]\frac{1}{5}[/tex] = 0.2Hz
