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Two inductors are connected in parallel to a 120 volt, 60 Hz line. The values are 5 H and 2 H. The total inductive reactance is

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TutorAnneidn

Answer:Total Inductive reactance XL =538.63 Ω

Explanation:

Parallel combination for Effective inductance is calculated as

L total =  [tex]\frac{1}{1/L1 + 1/L2 + ... 1/Ln}[/tex]

=[tex]\frac{1}{1/5 + 1/2}[/tex]

[tex]\frac{1}{0.2 + 0.5 \\}[/tex]

=[tex]\frac{1}{0.7}[/tex]

=1.42857H

Inductive reactance XL = 2 πFL

where f= frequency= 60Hz

L=  Effective inductance=1.42857H

Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857

=538.63Ω

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