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Answer:

Ans => C => 43.3%

Explanation:

2CO + O₂ => 2CO₂

Given     1g CO = 1g/28g·mol⁻¹ = 0.036 mol CO

b/c coefficient of CO = coefficient of CO₂ => moles CO₂ = 0.036 mol = 0.036mol x 44g/mol = 1.57 gCO₂ (theoretical yield)

%Yield = (actual yield/theoretical yield) x 100% = (0.68g/1.57g) x 100% = 43.3%

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