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What is an equation of the line that passes through the points (3, 0) and (6, -1)

Sagot :

Y= -1/3x + 1

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Answer:

(Note: This is assuming that the answer can be in any format.)

[tex]y - 0 = -\frac{1}{3} (x - 3)[/tex]

Step-by-step explanation:

When given at least two points, you can find write an equation using the point-slope formula: [tex]y - y_1 = m (x - x_1)[/tex]. The [tex]x_1[/tex] and [tex]y_1[/tex] are the x and y values from one point that need to be substituted in to make an equation, as well as the [tex]m[/tex] which represents the slope.

Find the slope by using the slope formula [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex] and the two points given:

[tex]\frac{-1-0}{6-3}[/tex]

[tex]\frac{-1}{3}[/tex]

So, the slope is [tex]-\frac{1}{3}[/tex].

Next, choose a point (in this case, I chose (3,0)) and substitute its x and y values into [tex]x_1[/tex] and [tex]y_1[/tex] respectively, and also substitute  [tex]-\frac{1}{3}[/tex] for m. This forms an equation of a line in point-slope formula:

[tex]y - 0 = -\frac{1}{3} (x - 3)[/tex]

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