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Answer:
0.670 mol
Explanation:
Step 1: Write the balanced reaction for the decomposition of alumina
2 Al₂O₃ ⇒ 4 Al + 3 O₂
Step 2: Calculate the moles corresponding to 34.2 g of Al₂O₃
The molar mass of Al₂O₃ is 101.96 g/mol.
34.2 g × 1 mol/101.96 g = 0.335 mol
Step 3: Calculate the moles of Al produced from 0.335 moles of Al₂O₃
The molar ratio of Al₂O₃ to Al is 2:4.
0.335 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃) = 0.670 mol Al