Answer:
C, F, D
Step-by-step explanation:
For each side of each triangle, think of the side as the hypotenuse of a right triangle. Then use the Pythagorean theorem to find the length of the hypotenuse, which is the side of the triangle.
Left problem:
From point C to point A, go 2 left and 7 up.
[tex] AC = \sqrt{2^2 + 7^2} = 7.3 [/tex]
From point A to point B, go 5 right and 1 down.
[tex] AB = \sqrt{5^2 + 1^2} = 5.1 [/tex]
From point B to point C, go 6 down and 3 left.
[tex] BC = \sqrt{6^2 + 3^2} = 6.7 [/tex]
Perimeter = 7.3 + 5.1 + 6.7 = 19.1
Do the same for the other triangles.
Middle problem:
From point F to point D, go 2 left and 7 up.
[tex] FD = \sqrt{2^2 + 7^2} = 7.3 [/tex]
From point D to point E, go 7 right and 2 down.
[tex] DE = \sqrt{7^2 + 2^2} = 7.3 [/tex]
From point E to point F, go 5 down and 5 left.
[tex] EF = \sqrt{5^2 + 5^2} = 7.1 [/tex]
Perimeter = 7.3 + 7.3 + 7.1 = 21.7
Right problem:
From point L to point J, go 7 left and 1 up.
[tex] LJ = \sqrt{7^2 + 1^2} = 7.1 [/tex]
From point J to point K, go 4 up and 5 right.
[tex] JK = \sqrt{4^2 + 5^2} = 6.4 [/tex]
From point K to point L, go 2 right and 5 down.
[tex] KL = \sqrt{2^2 + 5^2} = 5.4 [/tex]
Perimeter = 7.1 + 6.4 + 5.4 = 18.9
