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Answer:
x = 10; y = 10
Step-by-step explanation:
[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]
[tex] \cos( {theta} ) = \frac{adjacent}{hypotenuse} [/tex]
[tex] \tan( {theta} ) = \frac{opposite}{adjacent} [/tex]
theta = 45°
opposite = x
hypotenuse = 10√2
adjacent = y
[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]
[tex] \sin(45) = \frac{x}{10 \sqrt{2} } [/tex]
[tex] \sin(45) \times 10 \sqrt{2} = x[/tex]
[tex]10 = x[/tex]
[tex]x = 10[/tex]
[tex] \cos( {theta} ) = \frac{adjacent}{hypotenuse} [/tex]
[tex] \cos(45) = \frac{y}{10 \sqrt{2} } [/tex]
[tex] \cos(45) \times 10 \sqrt{2} = y[/tex]
[tex]10 = y[/tex]
[tex]y = 10[/tex]