Get the best answers to your questions with the help of IDNLearn.com's experts. Find the solutions you need quickly and accurately with help from our knowledgeable community.

Does the graph in Exercise 33 have a Hamilton path? If

so, find such a path. If it does not, give an argument to

show why no such path exist​


Sagot :

;

Answer:

there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .