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Sagot :
Answer:
[tex]h=4x^3+18[/tex]
Step-by-step explanation:
Given that,
The area of a triangle, [tex]A=14x^5 + 63x^2[/tex]
Base, [tex]b=7x^2[/tex]
We need to find the height of the triangle.
The formula for the area of the triangle is given by :
[tex]A=\dfrac{1}{2}\times b\times h\\\\\text{h is height}\\\\h=\dfrac{2A}{b}\\\\h=\dfrac{2\times (14x^5 + 63x^2)}{7x^2}\\\\h=\dfrac{2\times 7x^2(2x^3 + 9)}{7x^2}\\\\h=2(2x^3+9)\\\\=4x^3+18[/tex]
So, the height of the triangle is [tex]4x^3+18[/tex].
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