Well, we know standard form of quadratic equation : ax² + bx + c where,
a = Coefficient of x²
b = Coefficient of x
c = Constant term
We also equation for determinant :
⇒ b² - 4ac
Here, if value of determinant i.e. (b² - 4ac) = A perfect Square, then we can understand that the givdn equation is factorisable.
But, if the value of (b² - 4ac) ≠ A perfect square, then it will be considered as "Not factorisable"
Now let's calculate whether the equation is factorisable or not :
Comparing the given equation with ax² + bx + c, we get :
a = 1
b = -3
c = -54
Putting values in the determinant equation :
⇒ (-3)² - 4(1 × -54)
⇒ 9 + 216
⇒ 225
⇒ 15²
So, determinant = A perfect square
That means the given equation is factorisable.
Now let's factorize with by middle term splitting :
⇒ x² - 3x - 54
⇒ x² -(9 - 6)x - 54
⇒ x² - 9x + 6x - 54
⇒ x(x - 9) + 6(x - 9)
⇒ (x + 6)(x - 9) [Required Solution]
Hence, we get our required solution.
Hope this Helps (✿◡‿◡)
