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If 2^x3^y=18 and 2^x×3^y=36 then find the value of x and y​

Sagot :

Answer:

x = 1

y = 2

Step-by-step explanation:

x=1 and y=2.

step 1 ,

2^2x*3^y=36

3^y= 36/2^2x ———- equal 1

step 2,

put the value of 3^y in 2^x*3^y = 18 (equal 1)

WHEN BASES ARE SAME POWERS ARE SUBTRACTED IN CASE OF DIVISION.

Therefore, 2^x-2^2x= 1/2

2^-x= 1/2

(1/2)^x = 1/2

COMPARING THE POWERS BECAUSE THE BASE IS SAME.

x=1.

Now, putting the value of x=1 in 2^x*3^y = 18

y=2.

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