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Find the 62nd term of the following sequence:
(-21, – 27, - 33, - 39,...)

Sagot :

Kritika3375idn

Answer:

-387

Step-by-step explanation:

First term (T1) = -21 = a

second term (t2) = - 27

common difference (d) = t2 - t1 = - 27 + 21 = - 6

Now

Tn = a + ( n - 1) d

T62 = - 21 + ( 62 - 1 ) - 6

= - 21 -366

= -387

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